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9n^2-27n-486=0
a = 9; b = -27; c = -486;
Δ = b2-4ac
Δ = -272-4·9·(-486)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18225}=135$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-135}{2*9}=\frac{-108}{18} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+135}{2*9}=\frac{162}{18} =9 $
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